What is the equation of the line that goes through (-3,-1) and (3,3)?

Answer:see explanationStep-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )Calculate m using the slope formulam = (y₂ - y₁ ) / (x₂ - x₁ )with (x₁, y₁ ) = (- 3, - 1) and (x₂, y₂ ) = (3, 3)m = [tex]\frac{3+1}{3+3}[/tex] = [tex]\frac{4}{6}[/tex] = [tex]\frac{2}{3}[/tex], thusy = [tex]\frac{2}{3}[/tex] x + c ← is the partial equationTo find c substitute either of the 2 points into the partial equationUsing (3, 3), then3 = 2 + c ⇒ c = 3 - 2 = 1y = [tex]\frac{2}{3}[/tex] x + 1 ← equation of lineMultiply through by 33y = 2x + 3 ( subtract 3y from both sides )0 = 2x - 3y + 3 ( subtract 3 from both sides )- 3 = 2x - 3y, that is2x - 3y = - 3 ← in standard form